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The concepts I'm asking are specifically for a problem on the free Princeton Review practice exam ... so if anyone's taken it, it is the 3rd question in the PS section.
For those who don't know the question, I can't paste the whole question with the passage... so I'll try my best:
For something to be buffered does that mean the solution (in terms of an acid/base titration) has equal concentration of acid and its conjugate base? And does this mean that they have equal moles?
The question I'm have trouble with is a titration of a galvanic cell to cell potential against ion concentration.
The question asks what volume of .1M Ce4+ solution has to be added so that a buffer of Fe2+/Fe3+ could exist.
A: 15 mL
B: 25 mL
C: 35 mL
D: 45 mL
Now the passage gives three relevant factoids (at least one's that I've extracted):
(1) the cell starts with 50 mL of 0.05 M Fe2+
(2) a rxn btween Fe2+ and Ce4+ occurs: Fe2+ + Ce4+ -> Fe3+ + Ce3+
(3) a titration curve is given with eqv point = 30 mL of .10 M Ce4+ and half eqv point at 15 mL.
The correct answer expects you to use the titration curve and determine that 15 mL needs to be added b/c that is the half-eqv point.
But my confusion arises because adding 15 mL of 0.1 M Ce4+ equates to .0015 moles of Ce4+, while there are .0025 moles of Fe2+ to begin with. That would mean .0015 moles of Ce4+ react with Fe2+ leaving .0010 moles of Fe2+ in solution with .0015 moles of Fe3+... what kind of buffer is that???
For those who don't know the question, I can't paste the whole question with the passage... so I'll try my best:
For something to be buffered does that mean the solution (in terms of an acid/base titration) has equal concentration of acid and its conjugate base? And does this mean that they have equal moles?
The question I'm have trouble with is a titration of a galvanic cell to cell potential against ion concentration.
The question asks what volume of .1M Ce4+ solution has to be added so that a buffer of Fe2+/Fe3+ could exist.
A: 15 mL
B: 25 mL
C: 35 mL
D: 45 mL
Now the passage gives three relevant factoids (at least one's that I've extracted):
(1) the cell starts with 50 mL of 0.05 M Fe2+
(2) a rxn btween Fe2+ and Ce4+ occurs: Fe2+ + Ce4+ -> Fe3+ + Ce3+
(3) a titration curve is given with eqv point = 30 mL of .10 M Ce4+ and half eqv point at 15 mL.
The correct answer expects you to use the titration curve and determine that 15 mL needs to be added b/c that is the half-eqv point.
But my confusion arises because adding 15 mL of 0.1 M Ce4+ equates to .0015 moles of Ce4+, while there are .0025 moles of Fe2+ to begin with. That would mean .0015 moles of Ce4+ react with Fe2+ leaving .0010 moles of Fe2+ in solution with .0015 moles of Fe3+... what kind of buffer is that???