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Hey I know this question has been asked before but none of the other threads seem to really shed some clarity on the issue.
I have been working through the Kaplan High Yield problem solving guide (which I really like BTW). In the problems dealing with electrostatics the first problem says to use deltaU=qdeltaV for the change in electric potential energy.
However when we get to the third worked problem it says to solve for potential energy by using U=kq1q1/r. In its explanation it says
"Potential energy can only be defined as a relative value, but in these types of problems, it is easiest to use the definition that the potential energy is zero at infinite distance. This way you can use the formula U=kq1q2/r, which saves time as compared to using deltaU=qdeltaV by bypassing the step of first calculating V."
Basically, I don't understand the criteria behind when to use which equation and how using the definition of potential energy being zero at infinite distance allows you to use a particular equation.
Thanks for helping me!!!
I have been working through the Kaplan High Yield problem solving guide (which I really like BTW). In the problems dealing with electrostatics the first problem says to use deltaU=qdeltaV for the change in electric potential energy.
However when we get to the third worked problem it says to solve for potential energy by using U=kq1q1/r. In its explanation it says
"Potential energy can only be defined as a relative value, but in these types of problems, it is easiest to use the definition that the potential energy is zero at infinite distance. This way you can use the formula U=kq1q2/r, which saves time as compared to using deltaU=qdeltaV by bypassing the step of first calculating V."
Basically, I don't understand the criteria behind when to use which equation and how using the definition of potential energy being zero at infinite distance allows you to use a particular equation.
Thanks for helping me!!!