what is the correct electron configuration for Zn2+?

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

Smooth Operater

don't bug "operatEr"!
10+ Year Member
5+ Year Member
15+ Year Member
Joined
May 22, 2004
Messages
1,285
Reaction score
1
what is the correct electron configuration for Zn2+?

[Ar] 4s2,3d8
[Ar] 4s0,3d10

the right answer is [Ar] 4s0,3d10

but i thought 3d subshell has higher energy than 4s subshelll there electron should be removed first from 3d subshell.

Thanks!

Members don't see this ad.
 
You're right, but remember, the transition metals are special. They basically never follow the rules. That's what I tell myself when I don't know the answer, anyway.
 
remember, atoms/molecules always want to be in their lowest, most stable state.

Zn2+ is in a lower state when it's d-subshell is filled (i.e. 4s0 3d10), rather than when it's s-subshell is filled and it's d-subshelled has unpaired electrons (i.e. 4s2 3d8)......

the first case is paramagnetic and the second, correct case, is diamagnetic.

hopefully that makes sense.

jb!:)
 
Members don't see this ad :)
4S has more energy than 3D so 4S will always lose electrons first.
 
I'm confuzed...Zn2+ would have the same configuration as nickel and my periodic table shows the nickel config. as [Ar]3d84s2
 
so it fills the 4s orbital before the 3d, but empties the 4s before the 3d...right?
 
Top