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If the rate law for a reaction is second order as so:
rate=k[A]
What happens to the rate when the VOLUME of the system is DECREASED by 4 times? (at constant temperature)
I figured that the Pressure of the system would INCREASE by 4 times.
But what happens to the rate:
-Does the rate increase by 4 times?
-Or does it increase by 16 times?
I don't know the answer and was wondering if anyone else did.
rate=k[A]
What happens to the rate when the VOLUME of the system is DECREASED by 4 times? (at constant temperature)
I figured that the Pressure of the system would INCREASE by 4 times.
But what happens to the rate:
-Does the rate increase by 4 times?
-Or does it increase by 16 times?
I don't know the answer and was wondering if anyone else did.