Thermodynamic cycle (PV chart)

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danny89

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Generally speaking, to find out what work is between two points in the cycle, we can use W=PV, right?
Can someone explain their logic to the following:
200px-Stirling_Cycle.png

1 to 2: W= Negative; decrease in temp.
2 to 3: W=0; decrease in temp
3 to 4: W= Positive; increase in temp
4 to 1: W= 0; increase in temp

Thanks

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By the way, TBR specifically said we do not need to know this.
They said we just need to know how refrigerator works. Does it release heat? absorb heat? etc..
 
I don't understand how from point 1 to 2, temperature decreases while point 3 to 4, temperature increases.
 
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I don't understand how from point 1 to 2, temperature decreases while point 3 to 4, temperature increases.

From point 1 to 2, the system is doing work ON the surroundings by expanding. Energy is used in this process which lowers the energy of the system, thereby decreasing temperature.

From point 3 to 4, some outside force is doing work ON the system by compressing the volume. This adds energy to the system, increasing temperature.
 
I don't understand how from point 1 to 2, temperature decreases while point 3 to 4, temperature increases.

Don't make it too complicated for yourself.

W = PV
PV = nRT
So, W = nRT

Therefore,
1-->2:
P is -, V is +
So, if W = PV, then W = (-)(+) = - value overall, and since
W = nRT, then for constant nR, W = T and if W becomes - then W = -T by simply exchanging the sign of the equation by division of -1 (if you want to think about it that way).
 
For point 2 to 3 and from 4 to 1, there is no work for each(no change in volume, thus W=PV=0), so how come temperature decreases for 2 to 3 and increases for 4 to 1?
 
Short cut: The sign on work is opposite the sign of the change in volume and the direction of change in pressure indicates the direction of change in temperature.

Full explanation:

With respect to the gas you have to use the equation: W = - P(DeltaV)

1 to 2 Gas expands (volume is positive) and thus the work is negative. Conceptually, the gas does work on the system when it expands (ex: pushes the piston) and now the gas has gone down it's work capacity (it has lost some capacity to do work). The gas transfers kinetic energy from its molecules to move the piston and thus the molecules lose kinetic energy (basically losing temperature).

3 to 4 Gas compresses (volume is negative) and thus work is positive. Work is done on the gas by the piston as the piston compresses the gas and now the gas gains more work capacity (it now has the capacity to do more work). The gas gains internal energy and the molecules gain kinetic energy (basically increase in temperature).

2 to 3 Change in volume is 0 thus work is 0. The gas is at constant volume, however, pressure has decreased. Pressure for arguments sake is the rate and force that the gas molecules are colliding with the walls of their container. Since the molecules are hitting the walls with less pressure it's obvious that they've lost kinetic energy and thus there's a decrease in temperature.

4 to 1 Change in volume is 0 thus work is 0. The gas is at constant volume, however, the pressure has increased. The molecules start hitting the walls with greater force and now have greater kinetic energy, thus there's an increase in temperature.
 
4 to 1 Change in volume is 0 thus work is 0. The gas is at constant volume, however, the pressure has increased. The molecules start hitting the walls with greater force and now have greater kinetic energy, thus there's an increase in temperature.

I thought KE is only affected by T.
Is this because PV = nRT, where V is constant, n is constant, so as P increases, T goes up in this case?
 
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