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For this question....
So I get the solution (kind of). Yes, we're using pulleys so maybe we use less force, but that force is just applied over a larger distance so that in the end, total work done is the same.
BUT this is how I thought of it ... would really appreciate it if someone could tell me where exactly my flaw in thinking is:
I wanted to try to find the y component of the force because I knew that component would equal 40N if I assumed the the mass would be lifted at a constant velocity (a=0).... then somehow use SOHCAHTOA to get F in terms of Fy and then just multiply it by the distance to get work?
Although what also doesn't make sense to me is that the F in the y direction is a downwards vector which doesn't make sense to me because you need to use a upwards vector F to pull up the box?
Probably multiple issues with how I'm thinking lol ... any feedback is appreciated.
So I get the solution (kind of). Yes, we're using pulleys so maybe we use less force, but that force is just applied over a larger distance so that in the end, total work done is the same.
BUT this is how I thought of it ... would really appreciate it if someone could tell me where exactly my flaw in thinking is:
I wanted to try to find the y component of the force because I knew that component would equal 40N if I assumed the the mass would be lifted at a constant velocity (a=0).... then somehow use SOHCAHTOA to get F in terms of Fy and then just multiply it by the distance to get work?
Although what also doesn't make sense to me is that the F in the y direction is a downwards vector which doesn't make sense to me because you need to use a upwards vector F to pull up the box?
Probably multiple issues with how I'm thinking lol ... any feedback is appreciated.