Background question information:
A student applies a force to a stalled car over a distance delta x to increase its kinetic energy.
Please look at this image for the question & pictures of the graphs: IMG 2821
A. A
B. B
C. C
D. D
C) C
Their answer:
As the car is pushed farther and farther, it builds up kinetic energy. As the KE increases, its v2 increases. The relationship is v2 α x, which is not linear, so eliminate choices A & B.
It is best to plug in numbers and see how the two values relate to one another. If v is doubled, then x must increase by a factor of 4. This means that x changes more than v changes, so the graph should bend towards the x-axis. Remember,"graphs curve towards the axis of greatest change."
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QUestioN:
Why exactly is the answer C & not D???
W = F * d
W = deltaK = KE = 1/2mvf^2 - 1/2mvi^2
F * d = 1/2mvf^2
d = 1/2mvf2 / F
d is proportional to v^2
If you increase d by a factor of 2, then v^2 would increase by a factor of 4? right? or do I have this reversed?
A student applies a force to a stalled car over a distance delta x to increase its kinetic energy.
Please look at this image for the question & pictures of the graphs: IMG 2821
A. A
B. B
C. C
D. D
C) C
Their answer:
As the car is pushed farther and farther, it builds up kinetic energy. As the KE increases, its v2 increases. The relationship is v2 α x, which is not linear, so eliminate choices A & B.
It is best to plug in numbers and see how the two values relate to one another. If v is doubled, then x must increase by a factor of 4. This means that x changes more than v changes, so the graph should bend towards the x-axis. Remember,"graphs curve towards the axis of greatest change."
----------------------------------------------
QUestioN:
Why exactly is the answer C & not D???
W = F * d
W = deltaK = KE = 1/2mvf^2 - 1/2mvi^2
F * d = 1/2mvf^2
d = 1/2mvf2 / F
d is proportional to v^2
If you increase d by a factor of 2, then v^2 would increase by a factor of 4? right? or do I have this reversed?