EK orgo lecture 3 question # 52

[DAKAZA]

I understand that the ketone on the left side of the ring is reduced to a secondary alcohol but I can't figure out how the ester on the right side of the ring is converted to a primary alcohol just by adding acid and water. Can anyone help me with this? Thank you

Btw, this is from the EK review book (not the 1001 series).

---

Members don't see this ad.

 

[HawkeyePostOp]

It's a two-step reduction of a carboxylic acid.
Usually it works like this:

ROOH
+
1)LiAlH4
2)H+, H20
->
ROH