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Why wouldn't both Opening switch A and opening switch B affect the power drain on resistor III? If you opened switch A, wouldn't that mean that all of the current is now diverted to resistor III (thus changing the power because P = I^2 (R) and if you opened switch B, wouldn't that also change the power because that would mean 0 current is flowing through the circuit?
In the answer explanation, they say that the equivalent resistance would change, but the current and voltage drop through resistor III would be unaffected. How can you change the resistance without changing the current? I tried to draw it out and use numbers to figure it out but I got really lost.
In the answer explanation, they say that the equivalent resistance would change, but the current and voltage drop through resistor III would be unaffected. How can you change the resistance without changing the current? I tried to draw it out and use numbers to figure it out but I got really lost.