Hey Guys, the last # of the BS section (#146) really confused me... the thing is, in the chart they are measuring the amount of radioactive nuclei (basically the percentage of cells whose nuclei have radioactive thymine) from the sample of cells which they extract. The reason why this confuses me, is since DNA is replicated in a semi-conservative model, and since it had incorporated radioactive thymine, then the amount of radioactive nuclei should remain constant and not decrease... I have a feeling that in this question, they should rather imply "the relative amount of radioactivity within cell nuclei" and then, it will be obvious that during DNA synthesis, the amount will be larger compared to when the cell has separated its DNA, thus separating the amount of radioactivity within it.
In an experiment on the phases of the cell cycle, cultures of actively dividing, synchronized cells were exposed to radioactively labeled 2-deoxythymidine for 30 minutes, then rinsed to remove the unabsorbed label. At various times thereafter, groups of cells were removed from the cultures and the nuclei examined to determine their content of radioactive material. Results are shown in the figure below.
Based on the figure, what process was occurring during hours 3-13 after treatment with radioactive 2-deoxythymidine? A
) Mitosis B
) Meiosis C
) DNA synthesis
This item includes a description of an experiment in which actively-dividing, synchronized cells were exposed to radioactively labeled 2-deoxythymidine (the nitrogen base incorporated into DNA, but not RNA). After 30 minutes of exposure to the radioactively labeled substance, the cells were rinsed to remove unabsorbed label. At various times thereafter, a group of cells from the culture were examined to determine the quantity of radioactive material in the nuclei. The figure shows a peak in radioactivity between 3 and 13 hours after treatment. This peak represents DNA synthesis, since 2-deoxythymidine is a component of DNA, but not RNA or protein.
D
) RNA synthesis